Program for Sum of Digit using C language

    
Suppose we are considering Digit 234. We have output 2+3+4 =  9

#include<stdio.h>
#include<conio.h>
main()
{
          int num, rem, sum=0;
         clrscr();
         printf(" Enter any number :- ");
         scanf("%d"",&num);
         while(num!=0)
         {
                rem=num%10;
                sum=sum+rem;
                num=num/10;
         }
         printf(" Sum Of Digit :- %d ",sum);
         getch();

}

O/p : Enter any number :-  234
         Sum of Digit :-  9


Execution :
num =234 , sum =0
while( 234!=0)
{ 
      rem= num%10;     rem= 234%10 ;      rem=4
      sum=sum+rem;     sum=0+4;              sum=4
      num=num/10;       num=234/10          num=23
}
while(num!=23)
{
      rem= num%10;     rem= 23%10 ;      rem=3
      sum=sum+rem;     sum=4+3;            sum=7
      num=num/10;       num=23/10          num=2
}


while(num!=2)
{
      rem= num%10;     rem= 2%10 ;        rem=2
      sum=sum+rem;     sum=7;                 sum=9
      num=num/10;       num=234/10          num=0
}

while(num!=0)---> condition is false.

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Milan Tomic

Hi. I’m Designer of Blog Magic. I’m CEO/Founder of ThemeXpose. I’m Creative Art Director, Web Designer, UI/UX Designer, Interaction Designer, Industrial Designer, Web Developer, Business Enthusiast, StartUp Enthusiast, Speaker, Writer and Photographer. Inspired to make things looks better.

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